3.2 GENERAL STRUCTURE DATA Z88I1.TXT

Mind the following formats:
[Long] = 4 bytes or 8 bytes integer number
[Double] = 8 bytes floating point number, alternatively with or without point

1st input group, i. e. first line, contains:

Dimension of the structure (2 or 3)
Number of nodes of the FEA structure
Number of elements
Number of degrees of freedom
Number of material information lines
Coordinate flag KFLAG (0 or 1)
Beam flag IBFLAG (0 or 1)
Plate flag IPFLAG (0 or 1)
Surface and pressure loads flag IQFLAG (0 or 1)

Write all numbers into a line, separate at least by one blank respectively. All numbers here of the type [Long].

Explanation KFLAG:
At input of 0 the coordinates are expected cartesian while at input of 1 polar or cylindrical coordinates are expected. The latter are then converted into cartesian coordinates and thereupon stored in this form in Z88O0.TXT. Caution: The axially symmetric elements
No.6, 8 and 12  and 15 positively expect cylindrical coordinates, set KFLAG to 0 here!

Explanation IBFLAG:
If
Beams No.2 or Beams No.13 appear in the structure, then set beam flag IBFLAG to 1, otherwise it must be 0.

Example: A three-dimensional structure of Hexahedrons No.10 and Beams No.2 is supposed to have 10 elements. The coordinates are entered in cartesian coordinates, 3 material info lines, 270 degrees of freedom and 45 nodes. Thus : 3 45 10 270 3 0  1 0 0

Explanation IPFLAG:
If Plates
No.18, No.19 or No.20 appear in the structure, then set plate flag IPFLAG to 1, otherwise it must be 0.

Example: A two-dimensional structure of Plates No.20 is supposed to have 100 elements. The coordinates are entered in cylindrical coordinates, 2 material info lines, 540 degrees of freedom and 180 nodes. Thus : 2 180 100 540 2 1 0 1 0

Caution: This Z88 release allows only beams or plates in a structure, not both in the same structure, because the DOF of the beams and the plates are not compatible!

Explanation IQFLAG:

This flag controls if the surface and pressure loads file Z88I5.TXT is read (1) or not (0). The boundary conditions file Z88I2.TXT features constraints, defections and nodal forces. Surface and pressure loads may be defined in Z88I5.TXT, if needed.

 

Example 1:

A threedimensional structure of tetrahedrons No.16 features 100 elements, 180 nodes, 540 DOF, 1 material information line, no change of coordinate system, no beams, no plates, use the surface and pressure loads file Z88I5.TXT.

>Thus: 3  180  100  540  1  0  0  0  1

 

Example 2:

A plate structure of elements No.18 features 1000 elements, 2000 nodes, 3000 DOF, 3 material information lines, no change of coordinate system, no beams, use the surface and pressure loads file Z88I5.TXT.

 > Thus: 2  1000  2000  3000  3  0  0  1  1

2nd input group, starting with line 2, contains:
Coordinates, one line per node.

Node number, strictly ascending [Long]
Number of the degrees of freedom for this node [Long]
X-coordinate or, if KFLAG is 1, R- coordinate [Double]
Y-coordinate or, if KFLAG is 1, PHI-coordinate [Double]
Z-coordinate or, if KFLAG is 1, Z-coordinate [Double]

The Z coordinate can be dropped at 2-dimensionalen structures. Enter angles PHI in radian.
Write all numbers into a line, separate at least by one blank respectively.

Example 1: The node no.156 has 2 degrees of freedom and the coordinates X = 45.3 and Y = 89.7 . Thus : 156 2 45.3 89.7

Example 2: The node no.68 is supposed to have 6 degrees of freedom (a Beam No.2 is attached) and cylindrical coordinates R = 100. , PHI = 0.7854 (corresponds to 45 °), Z = 56.87. Thus: 68 6 100. 0.7854 56.87

3rd input group, starting after last node, contains:
Coincidence, two lines for every finite element

1st line:
Element number, strictly ascending
Element type (1 to 20)

Write all numbers into a line, separate at least by one blank respectively. All numbers here of the type [Long].

2nd line: Depending on element type
1st node number for coincidence
2nd node number for coincidence
.....
20th node number for coincidence

Write all numbers into a line, separate at least by one blank respectively. All numbers here of the type [Long].

Example: An Isoparametric Serendipity Plane Stress Element No.7 has element number 23. The coincidence has the global nodes 14, 8, 17, 20, 38, 51, 55, 34 (locally these are the nodes 1-2-3-4-5-6-7-8, see chapter 4.7) . Thus resulting in two lines:
23  7
14  8  17  20  38  51  55  34

4th input group, starting after last element, contains:
Material information, one line for each material information.

This material information line starts with element no. inclusively [Long]
This material information line ends with element no. inclusively [Long]
Youngs's Modulus [Double]
Poisson's Ratio [Double]
Integration order (0, 1, 2, 3, 4, 5, 7 or 13) [Long]
Cross section value QPARA [Double]

... And if beams (but not plates !) are defined in addition:
Second moment of inertia yy (bending around yy axis)
Max. distance from neutral axis yy
Second moment of inertia zz (bending around zz axis)
Max. distance from neutral axis zz
Second moment of area (torsion)
Second modulus (torsion)

... And if plates (but not beams !) are defined and IQFLAG = 0,  in addition:
surface load

Write all numbers into a line, separate at least by one blank respectively.

Explanation cross section value QPARA:
QPARA is element type-dependent, e.g. for hexahedrons QPARA is 0, for trusses QPARA is the cross-sectional area and for plane stress elements QPARA is the thickness. See
chapter 4.

Example: The structure has 34 finite elements No.7. The thicknesses is supposed to vary: Elements 1 to 11 thickness 10 mm, elements 12 to 28 15 mm and elements 29 to 34 now 18 mm. Material steel. Integration order is supposed to be 2. Thus three material information lines:

1

1

11

206000

0.3

2

10.

2

12

28

206000

0.3

2

15.

3

29

34

206000

0.3

2

18.