3.2
GENERAL STRUCTURE DATA Z88I1.TXT
Mind the following formats:
[Long] = 4 bytes or 8 bytes integer number
[Double] = 8 bytes floating point number, alternatively with or without
point
1st input group, i. e.
first line, contains:
Dimension of the
structure (2 or 3)
Number of nodes of the FEA structure
Number of elements
Number of degrees of freedom
Number of material information lines
Coordinate flag KFLAG (0 or 1)
Beam flag IBFLAG (0 or 1)
Plate flag IPFLAG (0 or 1)
Surface and pressure loads flag IQFLAG (0 or 1)
Write all numbers into a
line, separate at least by one blank respectively. All numbers here of
the type
[Long].
Explanation KFLAG:
At input of 0 the coordinates are expected cartesian while at input of
1 polar
or cylindrical coordinates are expected. The latter are then converted
into
cartesian coordinates and thereupon stored in this form in Z88O0.TXT.
Caution:
The axially symmetric elements No.6, 8 and 12 and 15 positively
expect cylindrical coordinates, set KFLAG to 0 here!
Explanation IBFLAG:
If Beams No.2
or Beams No.13
appear in the structure, then set beam flag
IBFLAG to 1, otherwise it must be 0.
Example: A three-dimensional structure of Hexahedrons
No.10 and Beams
No.2 is supposed to have
10 elements. The
coordinates are entered in cartesian coordinates, 3 material info
lines, 270
degrees of freedom and 45 nodes. Thus : 3 45 10 270 3 0 1
0 0
Explanation IPFLAG:
If Plates No.18, No.19 or No.20 appear in the structure, then set
plate flag IPFLAG to 1, otherwise it must be 0.
Example: A two-dimensional structure of
Plates No.20 is supposed to have 100 elements. The coordinates are
entered in
cylindrical coordinates, 2 material info lines, 540 degrees of freedom
and 180
nodes. Thus : 2 180 100 540 2 1 0 1
0
Caution: This Z88
release allows only beams or plates in a structure, not both in
the same
structure, because
the DOF of the beams and the plates
are not compatible!
Explanation IQFLAG:
This flag controls if the surface
and pressure loads file Z88I5.TXT is read (1) or not (0). The boundary
conditions file Z88I2.TXT features constraints, defections and nodal
forces.
Surface and pressure loads may be defined in Z88I5.TXT, if needed.
Example 1:
A threedimensional
structure of tetrahedrons No.16 features 100 elements, 180 nodes, 540
DOF, 1
material information line, no change of coordinate system, no beams, no
plates,
use the surface and pressure loads file Z88I5.TXT.
>Thus: 3 180
100 540 1
0 0 0 1
Example 2:
A plate structure of
elements No.18 features 1000 elements, 2000 nodes, 3000 DOF, 3 material
information lines, no change of coordinate system, no beams, use the
surface
and pressure loads file Z88I5.TXT.
> Thus: 2
1000 2000 3000 3 0
0 1 1
2nd input group,
starting with line 2, contains:
Coordinates, one
line per node.
Node number, strictly
ascending [Long]
Number of the degrees of freedom for this node [Long]
X-coordinate or, if KFLAG is 1, R- coordinate [Double]
Y-coordinate or, if KFLAG is 1, PHI-coordinate [Double]
Z-coordinate or, if KFLAG is 1, Z-coordinate [Double]
The Z coordinate can be
dropped at 2-dimensionalen structures. Enter angles PHI in radian.
Write all numbers into a line, separate at least by one blank
respectively.
Example 1: The node no.156 has 2 degrees of
freedom and the coordinates X = 45.3 and Y = 89.7 . Thus : 156 2
45.3 89.7
Example 2: The node no.68 is supposed to have
6 degrees of freedom (a Beam No.2 is attached) and cylindrical
coordinates R = 100. , PHI = 0.7854 (corresponds to 45 °), Z =
56.87. Thus: 68 6 100. 0.7854 56.87
3rd input group,
starting after last node, contains:
Coincidence, two
lines for every finite element
1st line:
Element number, strictly ascending
Element type (1 to 20)
Write all numbers into a
line, separate at least by one blank respectively. All numbers here of
the type
[Long].
2nd line: Depending on
element type
1st node number for coincidence
2nd node number for coincidence
.....
20th node number for coincidence
Write all numbers into a
line, separate at least by one blank respectively. All numbers here of
the type
[Long].
Example: An Isoparametric Serendipity Plane
Stress Element No.7 has element number 23. The coincidence has the
global nodes
14, 8, 17, 20, 38, 51, 55, 34 (locally these are the nodes
1-2-3-4-5-6-7-8, see
chapter 4.7)
. Thus resulting in two lines:
23 7
14 8
17 20 38
51 55 34
4th input group,
starting after last element, contains:
Material information, one line for each material information.
This material
information line starts with element no. inclusively [Long]
This material information line ends with element no. inclusively
[Long]
Youngs's Modulus [Double]
Poisson's Ratio [Double]
Integration order (0, 1, 2, 3, 4, 5, 7 or 13) [Long]
Cross section value QPARA [Double]
... And if beams (but
not plates !) are defined in addition:
Second
moment of inertia yy (bending around yy axis)
Max. distance from neutral axis yy
Second moment of inertia zz (bending around zz axis)
Max. distance from neutral axis zz
Second moment of area (torsion)
Second modulus (torsion)
... And if plates
(but not beams !) are defined and IQFLAG = 0,
in addition:
surface load
Write all numbers into a
line, separate at least by one blank respectively.
Explanation cross
section value QPARA:
QPARA is element type-dependent, e.g. for hexahedrons QPARA is 0, for
trusses
QPARA is the cross-sectional area and for plane stress elements QPARA
is the
thickness. See chapter 4.
Example: The structure has 34 finite
elements No.7. The thicknesses is supposed to vary: Elements 1 to 11
thickness
10 mm, elements 12 to 28 15 mm and elements 29 to 34 now 18 mm.
Material steel.
Integration order is supposed to be 2. Thus three material information
lines:
1 |
1 |
11 |
206000 |
0.3 |
2 |
10. |
2 |
12 |
28 |
206000 |
0.3 |
2 |
15. |
3 |
29 |
34 |
206000 |
0.3 |
2 |
18. |