The count of pattern letters determines the number of bytes used to represent a value. The symbol used in the pattern of letters can only be used in groups of 1, 2, or 4, for example, y, yy, or yyyy.
The following table shows the dateTime symbols for CWF binary data:
Symbol | Meaning | Example |
---|---|---|
y | year | 1996 |
M | month in year | 7 |
d | day in month | 10 |
H | hour in day (0-23) | 13 |
m | minute in hour | 30 |
s | second in minute | 55 |
S | millisecond | 978 |
X | Ignore on input |
The following example shows the C language structure tm with an integer of four bytes:
struct tm { int tm_sec; /* seconds after the minute - [0,59]*/ { int tm_min; /* minutes after the hour - [0,59]*/ { int tm_hour; /* hours since midnight - [0,23]*/ { int tm_mday; /* day of the month - [1,31]*/ { int tm_mon; /* months since January - [0,11]*/ { int tm_year; /* years since 1900 */ { int tm_wday; /* days since Sunday - [0,6]*/ { int tm_yday; /* days since January 1 - [0,365]*/ { int tm_isdst; /* daylight savings time flag */ };
You can format this structure by specifying the string "ssssmmmmHHHHddddMMMM+1yyyy+1900XXXXXXXXXXXX". The number of pattern letters determines the number of bytes. There are 36 A-Z characters specified in this pattern, which match the 36 byte structure tm. A field followed by a plus sign (+) has the succeeding numeric characters added to it. Therefore MMMM+1 adds one to the month, yyyy+1900 adds 1900 to the year. X expects one byte of input, but ignores its value. On output, it outputs the byte as 0.
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