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Topic Title: Capturing link module name via DXL Topic Summary: Created On: 1-Nov-2006 21:34 Status: Post and Reply |
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![]() Answer: Your code only sees links for source modules that are already loaded. Anyway, you need something like this: Module mLink = module(l) print "LinkModule name of link = " (fullName(mLink)) "\n" - Louie | |
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The below code does the following:
- For the selected object it will look at all incoming links no matter which link module a link may go through - For each of these links it will print out the target module quote: My question is how can I capture and the name of the link module that each of these links are going through? Thanks, ------------------------- pete.kowalski(at)motorola.com |
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Your code only sees links for source modules that are already loaded.
Anyway, you need something like this: Module mLink = module(l) print "LinkModule name of link = " (fullName(mLink)) "\n" - Louie |
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Louie,
You are the best! Ever thought of writing a DXL book? You are correct. The code I developed only works from source modules that are already opened. I designed it to run from an open module only. Thanks again. ------------------------- pete.kowalski(at)motorola.com |
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Capturing link module name via DXL
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