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Topic Title: Getting link module name from LinkRef Topic Summary: Can you? Created On: 18-Sep-2007 13:22 Status: Post and Reply |
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![]() Answer: David, The following code works, however, it does not work when you switch the outgoing links! Just incoming links. So what you'd have to do to make this work is for outgoing links, always open the target module and run this function there. Hope this helps! | |
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Does anyone know of a way to get the name of the link module using a LinkRef? I know there is the module(Link l) function but that doesn't really help me.
------------------------- David Pechacek AAI Services Textron dpechacek@sc-aaicorp.com David.Pechacek@gmail.com |
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David,
The following code works, however, it does not work when you switch the outgoing links! Just incoming links. So what you'd have to do to make this work is for outgoing links, always open the target module and run this function there. Hope this helps! ------------------------- Kevin Murphy http://www.baselinesinc.com The Requirements Management Experts |
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You don't need to open the target module for outgoing links. The module(Link l) command works fine without it being open since it gets the link module, not the target module. To get it to work for outgoing links you just change "LinkRef lr" to "Link l" and swap the "<-" to "->".
However the code you posted shows that the DXL Reference Manual is out of date since it does not document that the "module" function will take a LinkRef parameter. Only a Link parameter. Interesting. ------------------------- David Pechacek AAI Services Textron dpechacek@sc-aaicorp.com David.Pechacek@gmail.com Edited: 18-Sep-2007 at 18:49 by David Pechacek |
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